So I was looking at the size of 2/3" chips & found that none of the dimensions are 2/3" of an inch. Then read some more & found out that it goes back to old tube camera days & that:
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Engineers soon discovered that for various reasons the usable area of this imaging plane was approximately two thirds of the designated size. |
So a 2/3" chip is roughly 2/3 of a 2/3" diameter circle which means it has a diagonal of 0.43" or close to 4/9," which is smaller than 1/2". And 1/2" chips really are a 1/3" diagonal?!
Not sure if my mind is blown or just confused. I guess I need to do some more reading about tube cameras, cause this part still I don’t completely get:
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The size designation does not define the diagonal of the sensor area but rather the outer diameter of the long glass envelope of the tube. |
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Dimensions of a 2/3" chip:
4:3 Chip – 8.8mm x 6.6mm (0.35" x 0.26") – 11mm (0.43") diagonal
(And for HD http://www.panavision.co.nz/main/kba…eframelist.asp)
16:9 Chip – 9.6mm x 5.4mm (0.38" x 0.21") – 11mm (0.43") diagonal